On iOS and on OS X you sometimes need the User Interface to update after a short delay. The old way of doing it was calling the performSelector:withObject:afterDelay: selector on any NSObject subclass but that requires defining a new method in your class and you can only pass one object as a parameter.
Instead, you can use dispatch_after from the Grand Central Dispatch APIs to execute code within a block after a certain time interval. Don’t be afraid, it might be low-level C but you can cut and paste and just put your code inside and it will retain the variable scope that blocks usually do!
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double delayInSeconds = 0.5; dispatch_time_t popTime = dispatch_time(DISPATCH_TIME_NOW, delayInSeconds * NSEC_PER_SEC); dispatch_after(popTime, dispatch_get_main_queue(), ^(void){ // Your code here }); |
Thank you! 🙂
Thanks for this, just what I was looking for!
Here is how you can trigger a block after a delay in Swift:
runThisAfterDelay(seconds: 2) { () -> () in
print(“Prints this 2 seconds later in main queue”)
}
/// EZSwiftExtensions
func runThisAfterDelay(seconds seconds: Double, after: () -> ()) {
let time = dispatch_time(DISPATCH_TIME_NOW, Int64(seconds * Double(NSEC_PER_SEC)))
dispatch_after(time, dispatch_get_main_queue(), after)
}
Its included as a standard function in my repo:
https://github.com/goktugyil/EZSwiftExtensions
thx!
thanks i need this